Gujarati
Hindi
14.Waves and Sound
normal

The equation of a stationary wave is $Y = 10\,\sin \,\frac{{\pi x}}{4}\,\cos \,20\,\pi t$. The distance between two consecutive nodes in metres is

A

$4$

B

$2$

C

$5$

D

$8$

Solution

$\frac{{2\pi }}{\lambda } = \frac{\pi }{4}$

$ \Rightarrow \lambda  = 8$

Now distance between nodes $ = \lambda /2 = 4$

Standard 11
Physics

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